3/4x^2-9=39

Solution for 3/4x^2-9=39 equation:

3/4x^2-9=39

We move all terms to the left:

3/4x^2-9-(39)=0


Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

3/4x^2-48=0

We multiply all the terms by the denominator


-48*4x^2+3=0

Wy multiply elements

-192x^2+3=0

a = -192; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-192)·3
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-192}=\frac{-48}{-384}
=1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-192}=\frac{48}{-384}
=-1/8
$